Math Problems

MathematicsPrecalculusTrig Functions → Evaluating Trig Functions

Evaluate the following trigonometric expressions

## Questions

 $$tan(30^\text{o})$$ = ________ $$tan(180^\text{o})$$ = ________ $$tan(3 \pi / 2)$$ = ________ $$cos(\pi / 6)$$ = ________ $$tan(270^\text{o})$$ = ________ $$cos(5 \pi / 6)$$ = ________ $$cos(\pi / 4)$$ = ________ $$cos(30^\text{o})$$ = ________ $$sin(45^\text{o})$$ = ________ $$cos(60^\text{o})$$ = ________ $$cos(270^\text{o})$$ = ________ $$sin(5 \pi / 6)$$ = ________ $$cos(150^\text{o})$$ = ________ $$cos(2 \pi / 3)$$ = ________ $$sin(60^\text{o})$$ = ________ $$cos(180^\text{o})$$ = ________ $$tan(\pi / 6)$$ = ________ $$tan(\pi / 3)$$ = ________ $$tan(5 \pi / 6)$$ = ________ $$tan(60^\text{o})$$ = ________ $$sin(0)$$ = ________ $$sin(30^\text{o})$$ = ________ $$cos(45^\text{o})$$ = ________ $$cos(0^\text{o})$$ = ________ $$tan(\pi)$$ = ________ $$sin(\pi / 6)$$ = ________ $$sin(180^\text{o})$$ = ________ $$tan(150^\text{o})$$ = ________

 $$tan(30^\text{o}) = 1/\sqrt{3}$$ $$tan(180^\text{o}) = 0$$ $$tan(3 \pi / 2) = undefined$$ $$cos(\pi / 6) = \sqrt{3} / 2$$ $$tan(270^\text{o}) = undefined$$ $$cos(5 \pi / 6) = -\sqrt{3} / 2$$ $$cos(\pi / 4) = \sqrt{2} / 2$$ $$cos(30^\text{o}) = \sqrt{3} / 2$$ $$sin(45^\text{o}) = \sqrt{2} / 2$$ $$cos(60^\text{o}) = 1/2$$ $$cos(270^\text{o}) = 0$$ $$sin(5 \pi / 6) = 1/2$$ $$cos(150^\text{o}) = -\sqrt{3} / 2$$ $$cos(2 \pi / 3) = -1/2$$ $$sin(60^\text{o}) = \sqrt{3} / 2$$ $$cos(180^\text{o}) = -1$$ $$tan(\pi / 6) = 1/\sqrt{3}$$ $$tan(\pi / 3) = \sqrt{3}$$ $$tan(5 \pi / 6) = -1/\sqrt{3}$$ $$tan(60^\text{o}) = \sqrt{3}$$ $$sin(0) = 0$$ $$sin(30^\text{o}) = 1/2$$ $$cos(45^\text{o}) = \sqrt{2} / 2$$ $$cos(0^\text{o}) = 1$$ $$tan(\pi) = 0$$ $$sin(\pi / 6) = 1/2$$ $$sin(180^\text{o}) = 0$$ $$tan(150^\text{o}) = -1/\sqrt{3}$$
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