Math Problems

Find x-intercepts of the given quadratic equation

## Questions

 $$y = 4 x^2 + 8 x$$ $$y = x^2 + 9 x + 18$$ $$y = 2 x^2 -6 x$$ $$y = 4 x^2 -5 x + 1$$ $$y = 3 x^2 -6 x + 3$$ $$y = x^2 -x -20$$ $$y = x^2 -3 x -18$$ $$y = x^2 -7 x + 10$$ $$y = x^2 + 5 x + 6$$ $$y = x^2 + 6 x + 8$$ $$y = x^2 -8 x + 16$$ $$y = x^2 -3 x$$ $$y = x^2 + 2 x -3$$ $$y = 3 x^2 + 5 x -2$$ $$y = 4 x^2 -8 x$$ $$y = 3 x^2 -x -2$$ $$y = 2 x^2 -7 x + 3$$ $$y = 4 x^2 -3 x$$ $$y = 4 x^2 -14 x + 6$$ $$y = x^2 -1$$ $$y = x^2 -2 x -15$$ $$y = 3 x^2 -2 x -1$$ $$y = x^2 + 2 x -8$$ $$y = x^2 + 8 x + 12$$ $$y = x^2 + 12 x + 36$$ $$y = 4 x^2 + 5 x + 1$$ $$y = 2 x^2 + 2 x$$ $$y = 3 x^2 -7 x + 2$$

 $$y = 4 x^2 + 8 x$$ ⇒ $$0, -2$$ $$y = x^2 + 9 x + 18$$ ⇒ $$-6, -3$$ $$y = 2 x^2 -6 x$$ ⇒ $$0, 3$$ $$y = 4 x^2 -5 x + 1$$ ⇒ $$1 / 4, 1$$ $$y = 3 x^2 -6 x + 3$$ ⇒ $$1, 1$$ $$y = x^2 -x -20$$ ⇒ $$5, -4$$ $$y = x^2 -3 x -18$$ ⇒ $$6, -3$$ $$y = x^2 -7 x + 10$$ ⇒ $$5, 2$$ $$y = x^2 + 5 x + 6$$ ⇒ $$-3, -2$$ $$y = x^2 + 6 x + 8$$ ⇒ $$-2, -4$$ $$y = x^2 -8 x + 16$$ ⇒ $$4, 4$$ $$y = x^2 -3 x$$ ⇒ $$0, 3$$ $$y = x^2 + 2 x -3$$ ⇒ $$-3, 1$$ $$y = 3 x^2 + 5 x -2$$ ⇒ $$1 / 3, -2$$ $$y = 4 x^2 -8 x$$ ⇒ $$0, 2$$ $$y = 3 x^2 -x -2$$ ⇒ $$-2 / 3, 1$$ $$y = 2 x^2 -7 x + 3$$ ⇒ $$1 / 2, 3$$ $$y = 4 x^2 -3 x$$ ⇒ $$3 / 4, 0$$ $$y = 4 x^2 -14 x + 6$$ ⇒ $$1 / 2, 3$$ $$y = x^2 -1$$ ⇒ $$1, -1$$ $$y = x^2 -2 x -15$$ ⇒ $$5, -3$$ $$y = 3 x^2 -2 x -1$$ ⇒ $$-1 / 3, 1$$ $$y = x^2 + 2 x -8$$ ⇒ $$-4, 2$$ $$y = x^2 + 8 x + 12$$ ⇒ $$-6, -2$$ $$y = x^2 + 12 x + 36$$ ⇒ $$-6, -6$$ $$y = 4 x^2 + 5 x + 1$$ ⇒ $$-1 / 4, -1$$ $$y = 2 x^2 + 2 x$$ ⇒ $$0, -1$$ $$y = 3 x^2 -7 x + 2$$ ⇒ $$1 / 3, 2$$
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