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MathematicsPrecalculusQuadratic Equations → Factor Quadratic Equations

Instructions for problem set  Factor each quadratic equation

Questions


\(y = x^2 + 4 x\)

\(y = x^2 + 11 x + 30\)

\(y = 2 x^2 + 3 x + 1\)

\(y = x^2 -11 x + 30\)

\(y = x^2 + 2 x\)

\(y = 4 x^2 -10 x -6\)

\(y = x^2 -2 x -24\)

\(y = 4 x^2 + 10 x + 4\)

\(y = x^2 + 10 x + 25\)

\(y = 4 x^2 + x -3\)

\(y = 4 x^2 + 2 x\)

\(y = 2 x^2 + 6 x + 4\)

\(y = x^2 -4 x\)

\(y = 2 x^2 + 2 x\)

\(y = x^2 + 5 x + 6\)

\(y = 3 x^2 + 7 x -6\)

\(y = 3 x^2 + 3 x -6\)

\(y = 2 x^2 -3 x -9\)

\(y = 3 x^2 -3 x -6\)

\(y = x^2 + 9 x + 18\)

\(y = x^2 + 7 x + 10\)

\(y = x^2 -7 x + 10\)

\(y = x^2 + 2 x + 1\)

\(y = 2 x^2\)

\(y = 2 x^2 -x -1\)

\(y = 3 x^2 + 5 x + 2\)

\(y = 3 x^2 + 2 x -1\)

\(y = x^2 -3 x -18\)

Answers


\(y = x^2 + 4 x \) ⇒
\((x)(x + 4)\)

\(y = x^2 + 11 x + 30 \) ⇒
\((x + 6)(x + 5)\)

\(y = 2 x^2 + 3 x + 1 \) ⇒
\((2 x + 1)(x + 1)\)

\(y = x^2 -11 x + 30 \) ⇒
\((x -6)(x -5)\)

\(y = x^2 + 2 x \) ⇒
\((x + 2)(x)\)

\(y = 4 x^2 -10 x -6 \) ⇒
\(2(2 x + 1)(x -3)\)

\(y = x^2 -2 x -24 \) ⇒
\((x + 4)(x -6)\)

\(y = 4 x^2 + 10 x + 4 \) ⇒
\(2(2 x + 1)(x + 2)\)

\(y = x^2 + 10 x + 25 \) ⇒
\((x + 5)(x + 5)\)

\(y = 4 x^2 + x -3 \) ⇒
\((4 x -3)(x + 1)\)

\(y = 4 x^2 + 2 x \) ⇒
\(2(2 x + 1)(x)\)

\(y = 2 x^2 + 6 x + 4 \) ⇒
\(2(x + 1)(x + 2)\)

\(y = x^2 -4 x \) ⇒
\((x -4)(x)\)

\(y = 2 x^2 + 2 x \) ⇒
\(2(x + 1)(x)\)

\(y = x^2 + 5 x + 6 \) ⇒
\((x + 3)(x + 2)\)

\(y = 3 x^2 + 7 x -6 \) ⇒
\((3 x -2)(x + 3)\)

\(y = 3 x^2 + 3 x -6 \) ⇒
\(3(x -1)(x + 2)\)

\(y = 2 x^2 -3 x -9 \) ⇒
\((2 x + 3)(x -3)\)

\(y = 3 x^2 -3 x -6 \) ⇒
\(3(x + 1)(x -2)\)

\(y = x^2 + 9 x + 18 \) ⇒
\((x + 6)(x + 3)\)

\(y = x^2 + 7 x + 10 \) ⇒
\((x + 5)(x + 2)\)

\(y = x^2 -7 x + 10 \) ⇒
\((x -5)(x -2)\)

\(y = x^2 + 2 x + 1 \) ⇒
\((x + 1)(x + 1)\)

\(y = 2 x^2 \) ⇒
\(2(x)(x)\)

\(y = 2 x^2 -x -1 \) ⇒
\((2 x + 1)(x -1)\)

\(y = 3 x^2 + 5 x + 2 \) ⇒
\((3 x + 2)(x + 1)\)

\(y = 3 x^2 + 2 x -1 \) ⇒
\((3 x -1)(x + 1)\)

\(y = x^2 -3 x -18 \) ⇒
\((x -6)(x + 3)\)
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First Coefficient

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