Math Problems

## Questions

 $$y = 2 x^2 + 6 x$$ $$y = x^2 -5 x + 4$$ $$y = x^2 -2 x$$ $$y = x^2 -7 x + 10$$ $$y = 2 x^2 + 7 x + 3$$ $$y = 3 x^2 -6 x$$ $$y = 2 x^2 + 5 x + 3$$ $$y = x^2 + x -20$$ $$y = x^2 + 2 x -15$$ $$y = x^2 -x -30$$ $$y = 4 x^2 + 3 x -1$$ $$y = x^2 -4$$ $$y = 2 x^2 -8 x + 6$$ $$y = 2 x^2 + 7 x + 6$$ $$y = x^2 + 5 x$$ $$y = 2 x^2 + 3 x -9$$ $$y = x^2 -7 x + 10$$ $$y = x^2 + 6 x + 5$$ $$y = x^2 -11 x + 30$$ $$y = x^2 + 11 x + 30$$ $$y = x^2 + 3 x + 2$$ $$y = x^2 + 2 x$$ $$y = 2 x^2 -3 x -9$$ $$y = 3 x^2 -6 x + 3$$ $$y = 3 x^2$$ $$y = x^2 -3 x + 2$$ $$y = x^2 + 2 x -8$$ $$y = 4 x^2 + 11 x -3$$

 $$y = 2 x^2 + 6 x$$ ⇒ $$2(x)(x + 3)$$ $$y = x^2 -5 x + 4$$ ⇒ $$(x -4)(x -1)$$ $$y = x^2 -2 x$$ ⇒ $$(x -2)(x)$$ $$y = x^2 -7 x + 10$$ ⇒ $$(x -5)(x -2)$$ $$y = 2 x^2 + 7 x + 3$$ ⇒ $$(2 x + 1)(x + 3)$$ $$y = 3 x^2 -6 x$$ ⇒ $$3(x)(x -2)$$ $$y = 2 x^2 + 5 x + 3$$ ⇒ $$(2 x + 3)(x + 1)$$ $$y = x^2 + x -20$$ ⇒ $$(x + 5)(x -4)$$ $$y = x^2 + 2 x -15$$ ⇒ $$(x -3)(x + 5)$$ $$y = x^2 -x -30$$ ⇒ $$(x -6)(x + 5)$$ $$y = 4 x^2 + 3 x -1$$ ⇒ $$(4 x -1)(x + 1)$$ $$y = x^2 -4$$ ⇒ $$(x -2)(x + 2)$$ $$y = 2 x^2 -8 x + 6$$ ⇒ $$2(x -1)(x -3)$$ $$y = 2 x^2 + 7 x + 6$$ ⇒ $$(2 x + 3)(x + 2)$$ $$y = x^2 + 5 x$$ ⇒ $$(x)(x + 5)$$ $$y = 2 x^2 + 3 x -9$$ ⇒ $$(2 x -3)(x + 3)$$ $$y = x^2 -7 x + 10$$ ⇒ $$(x -2)(x -5)$$ $$y = x^2 + 6 x + 5$$ ⇒ $$(x + 1)(x + 5)$$ $$y = x^2 -11 x + 30$$ ⇒ $$(x -5)(x -6)$$ $$y = x^2 + 11 x + 30$$ ⇒ $$(x + 5)(x + 6)$$ $$y = x^2 + 3 x + 2$$ ⇒ $$(x + 1)(x + 2)$$ $$y = x^2 + 2 x$$ ⇒ $$(x + 2)(x)$$ $$y = 2 x^2 -3 x -9$$ ⇒ $$(2 x + 3)(x -3)$$ $$y = 3 x^2 -6 x + 3$$ ⇒ $$3(x -1)(x -1)$$ $$y = 3 x^2$$ ⇒ $$3(x)(x)$$ $$y = x^2 -3 x + 2$$ ⇒ $$(x -2)(x -1)$$ $$y = x^2 + 2 x -8$$ ⇒ $$(x -2)(x + 4)$$ $$y = 4 x^2 + 11 x -3$$ ⇒ $$(4 x -1)(x + 3)$$