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MathematicsPrecalculusQuadratic Equations → Factor Quadratic Equations

Instructions for problem set  Factor each quadratic equation

Questions


\(y = x^2 -x -20\)

\(y = 3 x^2 -5 x + 2\)

\(y = x^2 -2 x -8\)

\(y = 2 x^2 + x -6\)

\(y = 4 x^2 + 15 x + 9\)

\(y = x^2 -1\)

\(y = x^2 + x -2\)

\(y = 4 x^2 -x -3\)

\(y = 4 x^2 + 3 x\)

\(y = x^2 + 12 x + 36\)

\(y = 2 x^2 + 3 x -2\)

\(y = 2 x^2 -4 x -6\)

\(y = 4 x^2 + 13 x + 3\)

\(y = 2 x^2 + 4 x -6\)

\(y = x^2 + 2 x -24\)

\(y = x^2 -x -20\)

\(y = 4 x^2 + 10 x -6\)

\(y = x^2 + 6 x + 5\)

\(y = 3 x^2 + 11 x + 6\)

\(y = x^2 + 2 x -15\)

\(y = x^2 -4 x -12\)

\(y = x^2 -6 x + 5\)

\(y = x^2 + 2 x -8\)

\(y = x^2 -3 x -4\)

\(y = x^2 -8 x + 15\)

\(y = 2 x^2 + 6 x\)

\(y = x^2 -8 x + 12\)

\(y = 2 x^2 -x\)

Answers


\(y = x^2 -x -20 \) ⇒
\((x + 4)(x -5)\)

\(y = 3 x^2 -5 x + 2 \) ⇒
\((3 x -2)(x -1)\)

\(y = x^2 -2 x -8 \) ⇒
\((x -4)(x + 2)\)

\(y = 2 x^2 + x -6 \) ⇒
\((2 x -3)(x + 2)\)

\(y = 4 x^2 + 15 x + 9 \) ⇒
\((4 x + 3)(x + 3)\)

\(y = x^2 -1 \) ⇒
\((x + 1)(x -1)\)

\(y = x^2 + x -2 \) ⇒
\((x + 2)(x -1)\)

\(y = 4 x^2 -x -3 \) ⇒
\((4 x + 3)(x -1)\)

\(y = 4 x^2 + 3 x \) ⇒
\((4 x + 3)(x)\)

\(y = x^2 + 12 x + 36 \) ⇒
\((x + 6)(x + 6)\)

\(y = 2 x^2 + 3 x -2 \) ⇒
\((2 x -1)(x + 2)\)

\(y = 2 x^2 -4 x -6 \) ⇒
\(2(x + 1)(x -3)\)

\(y = 4 x^2 + 13 x + 3 \) ⇒
\((4 x + 1)(x + 3)\)

\(y = 2 x^2 + 4 x -6 \) ⇒
\(2(x -1)(x + 3)\)

\(y = x^2 + 2 x -24 \) ⇒
\((x + 6)(x -4)\)

\(y = x^2 -x -20 \) ⇒
\((x -5)(x + 4)\)

\(y = 4 x^2 + 10 x -6 \) ⇒
\(2(2 x -1)(x + 3)\)

\(y = x^2 + 6 x + 5 \) ⇒
\((x + 5)(x + 1)\)

\(y = 3 x^2 + 11 x + 6 \) ⇒
\((3 x + 2)(x + 3)\)

\(y = x^2 + 2 x -15 \) ⇒
\((x -3)(x + 5)\)

\(y = x^2 -4 x -12 \) ⇒
\((x + 2)(x -6)\)

\(y = x^2 -6 x + 5 \) ⇒
\((x -1)(x -5)\)

\(y = x^2 + 2 x -8 \) ⇒
\((x + 4)(x -2)\)

\(y = x^2 -3 x -4 \) ⇒
\((x -4)(x + 1)\)

\(y = x^2 -8 x + 15 \) ⇒
\((x -3)(x -5)\)

\(y = 2 x^2 + 6 x \) ⇒
\(2(x)(x + 3)\)

\(y = x^2 -8 x + 12 \) ⇒
\((x -6)(x -2)\)

\(y = 2 x^2 -x \) ⇒
\((2 x -1)(x)\)
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