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Mathematics → Precalculus → Quadratic Equations → Factor Quadratic Equations

Instructions for problem set  Factor each quadratic equation

Questions


\(y = 4 x^2 -10 x + 4\)

\(y = 2 x^2 -6 x + 4\)

\(y = 4 x^2 -7 x -2\)

\(y = x^2 -1\)

\(y = 3 x^2 -2 x -1\)

\(y = x^2 + 5 x + 6\)

\(y = x^2 -3 x\)

\(y = x^2 -5 x -6\)

\(y = 3 x^2 + x -2\)

\(y = x^2 -9\)

\(y = x^2 + x -20\)

\(y = x^2 + 3 x -18\)

\(y = 2 x^2 -2 x\)

\(y = 4 x^2 -2 x -2\)

\(y = x^2 -9 x + 18\)

\(y = x^2 -5 x\)

\(y = x^2 + x -6\)

\(y = 3 x^2 -7 x -6\)

\(y = x^2 -3 x -10\)

\(y = 4 x^2 + 6 x + 2\)

\(y = 3 x^2 -8 x -3\)

\(y = x^2 -5 x -6\)

\(y = x^2 + x -2\)

\(y = 3 x^2 + 2 x -1\)

\(y = x^2 -8 x + 16\)

\(y = 2 x^2 + 5 x + 2\)

\(y = x^2 -3 x -4\)

\(y = 3 x^2 + 7 x -6\)

Answers


\(y = 4 x^2 -10 x + 4 \) ⇒
\(2(2 x -1)(x -2)\)
\(y = 2 x^2 -6 x + 4 \) ⇒
\(2(x -1)(x -2)\)
\(y = 4 x^2 -7 x -2 \) ⇒
\((4 x + 1)(x -2)\)
\(y = x^2 -1 \) ⇒
\((x -1)(x + 1)\)

\(y = 3 x^2 -2 x -1 \) ⇒
\((3 x + 1)(x -1)\)
\(y = x^2 + 5 x + 6 \) ⇒
\((x + 2)(x + 3)\)
\(y = x^2 -3 x \) ⇒
\((x -3)(x)\)
\(y = x^2 -5 x -6 \) ⇒
\((x -6)(x + 1)\)

\(y = 3 x^2 + x -2 \) ⇒
\((3 x -2)(x + 1)\)
\(y = x^2 -9 \) ⇒
\((x -3)(x + 3)\)
\(y = x^2 + x -20 \) ⇒
\((x -4)(x + 5)\)
\(y = x^2 + 3 x -18 \) ⇒
\((x -3)(x + 6)\)

\(y = 2 x^2 -2 x \) ⇒
\(2(x)(x -1)\)
\(y = 4 x^2 -2 x -2 \) ⇒
\(2(2 x + 1)(x -1)\)
\(y = x^2 -9 x + 18 \) ⇒
\((x -6)(x -3)\)
\(y = x^2 -5 x \) ⇒
\((x -5)(x)\)

\(y = x^2 + x -6 \) ⇒
\((x + 3)(x -2)\)
\(y = 3 x^2 -7 x -6 \) ⇒
\((3 x + 2)(x -3)\)
\(y = x^2 -3 x -10 \) ⇒
\((x -5)(x + 2)\)
\(y = 4 x^2 + 6 x + 2 \) ⇒
\(2(2 x + 1)(x + 1)\)

\(y = 3 x^2 -8 x -3 \) ⇒
\((3 x + 1)(x -3)\)
\(y = x^2 -5 x -6 \) ⇒
\((x + 1)(x -6)\)
\(y = x^2 + x -2 \) ⇒
\((x + 2)(x -1)\)
\(y = 3 x^2 + 2 x -1 \) ⇒
\((3 x -1)(x + 1)\)

\(y = x^2 -8 x + 16 \) ⇒
\((x -4)(x -4)\)
\(y = 2 x^2 + 5 x + 2 \) ⇒
\((2 x + 1)(x + 2)\)
\(y = x^2 -3 x -4 \) ⇒
\((x + 1)(x -4)\)
\(y = 3 x^2 + 7 x -6 \) ⇒
\((3 x -2)(x + 3)\)
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