Math Problems

MathematicsPrecalculusLinear Equations → Linear Equation

Solve for the variable in the linear equation

## Questions

 $$4 b + 1 = 5 b - 2$$ $$- 2 b - 1 = 4 b + 3$$ $$y - 3 = 2 y + 1$$ $$2 c + 3 = 6 c - 3$$ $$4 x - 1 = -3$$ $$4 - 2 y = - 4 y - 1$$ $$a + 5 = 4$$ $$10 - 6 a = 5 - 3 a$$ $$5 c - 2 = 11 c + 2$$ $$5 a - 1 = 6 a + 2$$ $$- 3 c = - c - 4$$ $$3 - 2 b = 4 - 7 b$$ $$7 - 2 a = 3 - 7 a$$ $$- 2 x - 3 = - 3 x - 4$$ $$b - 4 = 6 b - 4$$ $$2 - 6 x = - 4 x$$ $$- 5 y - 3 = 2 - 3 y$$ $$5 c - 2 = 10 c - 6$$ $$- 2 c - 10 = 2 c - 6$$ $$3 x - 2 = 2 - 2 x$$ $$6 - 2 b = b + 1$$ $$3 x - 1 = x + 1$$ $$1 = 2 y - 4$$ $$4 x - 4 = 2 x - 1$$ $$4 - 4 b = 2 - 2 b$$ $$a - 3 = 2 - 3 a$$ $$5 y = 2 y - 2$$ $$- 2 y - 10 = - y - 6$$

## Answers

 $$4 b + 1 = 5 b - 2$$ ⇒ $$b = 3$$ $$- 2 b - 1 = 4 b + 3$$ ⇒ $$b = - \frac{2}{3}$$ $$y - 3 = 2 y + 1$$ ⇒ $$y = -4$$ $$2 c + 3 = 6 c - 3$$ ⇒ $$c = \frac{3}{2}$$ $$4 x - 1 = -3$$ ⇒ $$x = - \frac{1}{2}$$ $$4 - 2 y = - 4 y - 1$$ ⇒ $$y = - \frac{5}{2}$$ $$a + 5 = 4$$ ⇒ $$a = -1$$ $$10 - 6 a = 5 - 3 a$$ ⇒ $$a = \frac{5}{3}$$ $$5 c - 2 = 11 c + 2$$ ⇒ $$c = - \frac{2}{3}$$ $$5 a - 1 = 6 a + 2$$ ⇒ $$a = -3$$ $$- 3 c = - c - 4$$ ⇒ $$c = 2$$ $$3 - 2 b = 4 - 7 b$$ ⇒ $$b = \frac{1}{5}$$ $$7 - 2 a = 3 - 7 a$$ ⇒ $$a = - \frac{4}{5}$$ $$- 2 x - 3 = - 3 x - 4$$ ⇒ $$x = -1$$ $$b - 4 = 6 b - 4$$ ⇒ $$b = 0$$ $$2 - 6 x = - 4 x$$ ⇒ $$x = 1$$ $$- 5 y - 3 = 2 - 3 y$$ ⇒ $$y = - \frac{5}{2}$$ $$5 c - 2 = 10 c - 6$$ ⇒ $$c = \frac{4}{5}$$ $$- 2 c - 10 = 2 c - 6$$ ⇒ $$c = -1$$ $$3 x - 2 = 2 - 2 x$$ ⇒ $$x = \frac{4}{5}$$ $$6 - 2 b = b + 1$$ ⇒ $$b = \frac{5}{3}$$ $$3 x - 1 = x + 1$$ ⇒ $$x = 1$$ $$1 = 2 y - 4$$ ⇒ $$y = \frac{5}{2}$$ $$4 x - 4 = 2 x - 1$$ ⇒ $$x = \frac{3}{2}$$ $$4 - 4 b = 2 - 2 b$$ ⇒ $$b = 1$$ $$a - 3 = 2 - 3 a$$ ⇒ $$a = \frac{5}{4}$$ $$5 y = 2 y - 2$$ ⇒ $$y = - \frac{2}{3}$$ $$- 2 y - 10 = - y - 6$$ ⇒ $$y = -4$$
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