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MathematicsArithmeticFractions → Adding Fractions

Instructions for problem set  Get a common denominator in order to evaluate the following

Questions


\(\frac{1}{2} + \frac{1}{8} =\) _______

\(\frac{6}{7} + \frac{1}{3} =\) _______

\(\frac{2}{3} - \frac{1}{2} =\) _______

\(\frac{3}{4} - \frac{1}{9} =\) _______

\(\frac{1}{3} + \frac{1}{4} =\) _______

\(\frac{4}{5} + \frac{1}{3} =\) _______

\(\frac{3}{4} + \frac{1}{3} =\) _______

\(\frac{3}{5} + \frac{8}{9} =\) _______

\(\frac{6}{7} - \frac{2}{7} =\) _______

\(\frac{1}{7} + \frac{5}{8} =\) _______

\(\frac{2}{5} + \frac{8}{9} =\) _______

\(\frac{1}{2} - \frac{1}{4} =\) _______

\(\frac{3}{4} + \frac{1}{8} =\) _______

\(\frac{1}{2} + \frac{1}{3} =\) _______

\(\frac{1}{2} - \frac{4}{9} =\) _______

\(\frac{5}{6} - \frac{7}{9} =\) _______

\(\frac{7}{9} + \frac{8}{9} =\) _______

\(\frac{5}{6} + \frac{3}{8} =\) _______

\(\frac{2}{5} - \frac{3}{7} =\) _______

\(\frac{1}{4} + \frac{2}{3} =\) _______

\(\frac{1}{5} - \frac{1}{4} =\) _______

\(\frac{2}{7} + \frac{2}{3} =\) _______

\(\frac{1}{7} - \frac{7}{8} =\) _______

\(\frac{1}{3} + \frac{2}{3} =\) _______

\(\frac{1}{2} + \frac{5}{7} =\) _______

\(\frac{1}{8} + \frac{5}{9} =\) _______

\(\frac{1}{5} - \frac{1}{9} =\) _______

\(\frac{2}{9} + \frac{2}{3} =\) _______

Answers


\(\frac{1}{2} + \frac{1}{8} = \frac{5}{8}\)

\(\frac{6}{7} + \frac{1}{3} = \frac{25}{21}\)

\(\frac{2}{3} - \frac{1}{2} = \frac{1}{6}\)

\(\frac{3}{4} - \frac{1}{9} = \frac{23}{36}\)

\(\frac{1}{3} + \frac{1}{4} = \frac{7}{12}\)

\(\frac{4}{5} + \frac{1}{3} = \frac{17}{15}\)

\(\frac{3}{4} + \frac{1}{3} = 1 \frac{1}{12}\)

\(\frac{3}{5} + \frac{8}{9} = \frac{67}{45}\)

\(\frac{6}{7} - \frac{2}{7} = \frac{4}{7}\)

\(\frac{1}{7} + \frac{5}{8} = \frac{43}{56}\)

\(\frac{2}{5} + \frac{8}{9} = 1 \frac{13}{45}\)

\(\frac{1}{2} - \frac{1}{4} = \frac{1}{4}\)

\(\frac{3}{4} + \frac{1}{8} = \frac{7}{8}\)

\(\frac{1}{2} + \frac{1}{3} = \frac{5}{6}\)

\(\frac{1}{2} - \frac{4}{9} = \frac{1}{18}\)

\(\frac{5}{6} - \frac{7}{9} = \frac{1}{18}\)

\(\frac{7}{9} + \frac{8}{9} = 1 \frac{2}{3}\)

\(\frac{5}{6} + \frac{3}{8} = \frac{29}{24}\)

\(\frac{2}{5} - \frac{3}{7} = \frac{-1}{35}\)

\(\frac{1}{4} + \frac{2}{3} = \frac{11}{12}\)

\(\frac{1}{5} - \frac{1}{4} = \frac{-1}{20}\)

\(\frac{2}{7} + \frac{2}{3} = \frac{20}{21}\)

\(\frac{1}{7} - \frac{7}{8} = \frac{-41}{56}\)

\(\frac{1}{3} + \frac{2}{3} = 1\)

\(\frac{1}{2} + \frac{5}{7} = 1 \frac{3}{14}\)

\(\frac{1}{8} + \frac{5}{9} = \frac{49}{72}\)

\(\frac{1}{5} - \frac{1}{9} = \frac{4}{45}\)

\(\frac{2}{9} + \frac{2}{3} = \frac{8}{9}\)
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