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MathematicsArithmeticFractions → Adding Fractions

Instructions for problem set  Get a common denominator in order to evaluate the following

Questions


\(\frac{2}{3} + \frac{4}{7} =\) _______

\(\frac{2}{5} - \frac{2}{3} =\) _______

\(\frac{4}{5} - \frac{2}{5} =\) _______

\(\frac{5}{8} - \frac{4}{9} =\) _______

\(\frac{2}{5} - \frac{1}{3} =\) _______

\(\frac{3}{4} - \frac{1}{9} =\) _______

\(\frac{5}{9} + \frac{2}{3} =\) _______

\(\frac{1}{2} - \frac{1}{4} =\) _______

\(\frac{2}{3} + \frac{3}{8} =\) _______

\(\frac{7}{8} + \frac{7}{9} =\) _______

\(\frac{1}{8} + \frac{4}{9} =\) _______

\(\frac{1}{2} + \frac{8}{9} =\) _______

\(\frac{2}{3} + \frac{1}{2} =\) _______

\(\frac{3}{5} - \frac{1}{2} =\) _______

\(\frac{2}{3} + \frac{8}{9} =\) _______

\(\frac{3}{4} + \frac{5}{9} =\) _______

\(\frac{1}{3} + \frac{4}{9} =\) _______

\(\frac{1}{5} - \frac{3}{8} =\) _______

\(\frac{1}{2} + \frac{3}{5} =\) _______

\(\frac{2}{3} + \frac{7}{9} =\) _______

\(\frac{2}{3} + \frac{1}{2} =\) _______

\(\frac{1}{7} - \frac{1}{3} =\) _______

\(\frac{1}{2} - \frac{1}{4} =\) _______

\(\frac{5}{7} - \frac{5}{9} =\) _______

\(\frac{1}{4} - \frac{4}{7} =\) _______

\(\frac{3}{4} - \frac{4}{7} =\) _______

\(\frac{3}{4} - \frac{5}{7} =\) _______

\(\frac{1}{3} - \frac{1}{4} =\) _______

Answers


\(\frac{2}{3} + \frac{4}{7} = \frac{26}{21}\)

\(\frac{2}{5} - \frac{2}{3} = \frac{-4}{15}\)

\(\frac{4}{5} - \frac{2}{5} = \frac{2}{5}\)

\(\frac{5}{8} - \frac{4}{9} = \frac{13}{72}\)

\(\frac{2}{5} - \frac{1}{3} = \frac{1}{15}\)

\(\frac{3}{4} - \frac{1}{9} = \frac{23}{36}\)

\(\frac{5}{9} + \frac{2}{3} = 1 \frac{2}{9}\)

\(\frac{1}{2} - \frac{1}{4} = \frac{1}{4}\)

\(\frac{2}{3} + \frac{3}{8} = 1 \frac{1}{24}\)

\(\frac{7}{8} + \frac{7}{9} = \frac{119}{72}\)

\(\frac{1}{8} + \frac{4}{9} = \frac{41}{72}\)

\(\frac{1}{2} + \frac{8}{9} = 1 \frac{7}{18}\)

\(\frac{2}{3} + \frac{1}{2} = 1 \frac{1}{6}\)

\(\frac{3}{5} - \frac{1}{2} = \frac{1}{10}\)

\(\frac{2}{3} + \frac{8}{9} = 1 \frac{5}{9}\)

\(\frac{3}{4} + \frac{5}{9} = \frac{47}{36}\)

\(\frac{1}{3} + \frac{4}{9} = \frac{7}{9}\)

\(\frac{1}{5} - \frac{3}{8} = \frac{-7}{40}\)

\(\frac{1}{2} + \frac{3}{5} = 1 \frac{1}{10}\)

\(\frac{2}{3} + \frac{7}{9} = 1 \frac{4}{9}\)

\(\frac{2}{3} + \frac{1}{2} = 1 \frac{1}{6}\)

\(\frac{1}{7} - \frac{1}{3} = \frac{-4}{21}\)

\(\frac{1}{2} - \frac{1}{4} = \frac{1}{4}\)

\(\frac{5}{7} - \frac{5}{9} = \frac{10}{63}\)

\(\frac{1}{4} - \frac{4}{7} = \frac{-9}{28}\)

\(\frac{3}{4} - \frac{4}{7} = \frac{5}{28}\)

\(\frac{3}{4} - \frac{5}{7} = \frac{1}{28}\)

\(\frac{1}{3} - \frac{1}{4} = \frac{1}{12}\)
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