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MathematicsArithmeticFractions → Adding Fractions

Instructions for problem set  Get a common denominator in order to evaluate the following

Questions


\(\frac{2}{7} + \frac{3}{8} =\) _______

\(\frac{2}{5} - \frac{3}{8} =\) _______

\(\frac{3}{8} - \frac{7}{9} =\) _______

\(\frac{2}{7} - \frac{1}{9} =\) _______

\(\frac{1}{2} + \frac{1}{2} =\) _______

\(\frac{3}{4} + \frac{5}{8} =\) _______

\(\frac{1}{3} - \frac{2}{7} =\) _______

\(\frac{3}{5} + \frac{2}{3} =\) _______

\(\frac{1}{2} + \frac{1}{8} =\) _______

\(\frac{8}{9} + \frac{2}{9} =\) _______

\(\frac{1}{2} - \frac{5}{6} =\) _______

\(\frac{1}{2} - \frac{2}{7} =\) _______

\(\frac{5}{6} + \frac{5}{6} =\) _______

\(\frac{1}{2} - \frac{1}{3} =\) _______

\(\frac{1}{2} + \frac{2}{3} =\) _______

\(\frac{2}{3} + \frac{4}{7} =\) _______

\(\frac{3}{5} + \frac{1}{3} =\) _______

\(\frac{3}{5} - \frac{1}{2} =\) _______

\(\frac{3}{4} + \frac{4}{7} =\) _______

\(\frac{1}{7} - \frac{5}{9} =\) _______

\(\frac{1}{3} - \frac{3}{4} =\) _______

\(\frac{1}{2} + \frac{1}{3} =\) _______

\(\frac{4}{7} + \frac{1}{2} =\) _______

\(\frac{5}{6} + \frac{1}{3} =\) _______

\(\frac{4}{5} + \frac{1}{9} =\) _______

\(\frac{5}{6} + \frac{5}{9} =\) _______

\(\frac{1}{2} + \frac{3}{4} =\) _______

\(\frac{2}{3} + \frac{1}{2} =\) _______

Answers


\(\frac{2}{7} + \frac{3}{8} = \frac{37}{56}\)

\(\frac{2}{5} - \frac{3}{8} = \frac{1}{40}\)

\(\frac{3}{8} - \frac{7}{9} = \frac{-29}{72}\)

\(\frac{2}{7} - \frac{1}{9} = \frac{11}{63}\)

\(\frac{1}{2} + \frac{1}{2} = 1\)

\(\frac{3}{4} + \frac{5}{8} = 1 \frac{3}{8}\)

\(\frac{1}{3} - \frac{2}{7} = \frac{1}{21}\)

\(\frac{3}{5} + \frac{2}{3} = 1 \frac{4}{15}\)

\(\frac{1}{2} + \frac{1}{8} = \frac{5}{8}\)

\(\frac{8}{9} + \frac{2}{9} = \frac{10}{9}\)

\(\frac{1}{2} - \frac{5}{6} = \frac{-1}{3}\)

\(\frac{1}{2} - \frac{2}{7} = \frac{3}{14}\)

\(\frac{5}{6} + \frac{5}{6} = \frac{5}{3}\)

\(\frac{1}{2} - \frac{1}{3} = \frac{1}{6}\)

\(\frac{1}{2} + \frac{2}{3} = 1 \frac{1}{6}\)

\(\frac{2}{3} + \frac{4}{7} = \frac{26}{21}\)

\(\frac{3}{5} + \frac{1}{3} = \frac{14}{15}\)

\(\frac{3}{5} - \frac{1}{2} = \frac{1}{10}\)

\(\frac{3}{4} + \frac{4}{7} = 1 \frac{9}{28}\)

\(\frac{1}{7} - \frac{5}{9} = \frac{-26}{63}\)

\(\frac{1}{3} - \frac{3}{4} = \frac{-5}{12}\)

\(\frac{1}{2} + \frac{1}{3} = \frac{5}{6}\)

\(\frac{4}{7} + \frac{1}{2} = 1 \frac{1}{14}\)

\(\frac{5}{6} + \frac{1}{3} = 1 \frac{1}{6}\)

\(\frac{4}{5} + \frac{1}{9} = \frac{41}{45}\)

\(\frac{5}{6} + \frac{5}{9} = 1 \frac{7}{18}\)

\(\frac{1}{2} + \frac{3}{4} = \frac{5}{4}\)

\(\frac{2}{3} + \frac{1}{2} = \frac{7}{6}\)
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