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MathematicsArithmeticFractions → Adding Fractions

Instructions for problem set  Get a common denominator in order to evaluate the following

Questions


\(\frac{6}{7} - \frac{2}{9} =\) _______

\(\frac{1}{4} + \frac{4}{9} =\) _______

\(\frac{2}{3} + \frac{1}{3} =\) _______

\(\frac{1}{4} - \frac{1}{2} =\) _______

\(\frac{1}{2} + \frac{6}{7} =\) _______

\(\frac{1}{2} - \frac{1}{7} =\) _______

\(\frac{1}{3} - \frac{2}{3} =\) _______

\(\frac{1}{2} + \frac{1}{2} =\) _______

\(\frac{2}{7} - \frac{7}{9} =\) _______

\(\frac{1}{6} - \frac{1}{7} =\) _______

\(\frac{1}{7} + \frac{1}{7} =\) _______

\(\frac{1}{3} - \frac{5}{9} =\) _______

\(\frac{5}{6} + \frac{1}{2} =\) _______

\(\frac{5}{7} - \frac{1}{9} =\) _______

\(\frac{5}{6} + \frac{2}{3} =\) _______

\(\frac{1}{2} - \frac{1}{5} =\) _______

\(\frac{5}{8} - \frac{4}{9} =\) _______

\(\frac{1}{4} - \frac{5}{7} =\) _______

\(\frac{1}{2} + \frac{2}{3} =\) _______

\(\frac{2}{7} + \frac{2}{7} =\) _______

\(\frac{1}{4} - \frac{7}{9} =\) _______

\(\frac{1}{2} - \frac{4}{9} =\) _______

\(\frac{2}{7} + \frac{8}{9} =\) _______

\(\frac{1}{5} + \frac{1}{2} =\) _______

\(\frac{7}{8} + \frac{3}{8} =\) _______

\(\frac{4}{7} + \frac{7}{9} =\) _______

\(\frac{3}{5} + \frac{1}{2} =\) _______

\(\frac{2}{7} + \frac{6}{7} =\) _______

Answers


\(\frac{6}{7} - \frac{2}{9} = \frac{40}{63}\)

\(\frac{1}{4} + \frac{4}{9} = \frac{25}{36}\)

\(\frac{2}{3} + \frac{1}{3} = 1\)

\(\frac{1}{4} - \frac{1}{2} = \frac{-1}{4}\)

\(\frac{1}{2} + \frac{6}{7} = 1 \frac{5}{14}\)

\(\frac{1}{2} - \frac{1}{7} = \frac{5}{14}\)

\(\frac{1}{3} - \frac{2}{3} = \frac{-1}{3}\)

\(\frac{1}{2} + \frac{1}{2} = 1\)

\(\frac{2}{7} - \frac{7}{9} = \frac{-31}{63}\)

\(\frac{1}{6} - \frac{1}{7} = \frac{1}{42}\)

\(\frac{1}{7} + \frac{1}{7} = \frac{2}{7}\)

\(\frac{1}{3} - \frac{5}{9} = \frac{-2}{9}\)

\(\frac{5}{6} + \frac{1}{2} = \frac{4}{3}\)

\(\frac{5}{7} - \frac{1}{9} = \frac{38}{63}\)

\(\frac{5}{6} + \frac{2}{3} = \frac{3}{2}\)

\(\frac{1}{2} - \frac{1}{5} = \frac{3}{10}\)

\(\frac{5}{8} - \frac{4}{9} = \frac{13}{72}\)

\(\frac{1}{4} - \frac{5}{7} = \frac{-13}{28}\)

\(\frac{1}{2} + \frac{2}{3} = 1 \frac{1}{6}\)

\(\frac{2}{7} + \frac{2}{7} = \frac{4}{7}\)

\(\frac{1}{4} - \frac{7}{9} = \frac{-19}{36}\)

\(\frac{1}{2} - \frac{4}{9} = \frac{1}{18}\)

\(\frac{2}{7} + \frac{8}{9} = \frac{74}{63}\)

\(\frac{1}{5} + \frac{1}{2} = \frac{7}{10}\)

\(\frac{7}{8} + \frac{3}{8} = 1 \frac{1}{4}\)

\(\frac{4}{7} + \frac{7}{9} = \frac{85}{63}\)

\(\frac{3}{5} + \frac{1}{2} = 1 \frac{1}{10}\)

\(\frac{2}{7} + \frac{6}{7} = 1 \frac{1}{7}\)
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