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MathematicsArithmeticFractions → Adding Fractions

Instructions for problem set  Get a common denominator in order to evaluate the following

Questions


\(\frac{5}{7} - \frac{4}{9} =\) _______

\(\frac{2}{7} + \frac{6}{7} =\) _______

\(\frac{5}{8} - \frac{3}{8} =\) _______

\(\frac{2}{3} - \frac{1}{9} =\) _______

\(\frac{2}{5} + \frac{3}{4} =\) _______

\(\frac{1}{2} + \frac{4}{7} =\) _______

\(\frac{5}{6} + \frac{1}{2} =\) _______

\(\frac{1}{2} + \frac{3}{8} =\) _______

\(\frac{7}{8} + \frac{3}{8} =\) _______

\(\frac{1}{2} + \frac{5}{6} =\) _______

\(\frac{1}{7} + \frac{8}{9} =\) _______

\(\frac{1}{3} + \frac{5}{9} =\) _______

\(\frac{6}{7} + \frac{4}{7} =\) _______

\(\frac{1}{4} - \frac{3}{4} =\) _______

\(\frac{1}{7} - \frac{5}{8} =\) _______

\(\frac{7}{8} + \frac{3}{4} =\) _______

\(\frac{1}{2} - \frac{7}{8} =\) _______

\(\frac{1}{6} - \frac{1}{6} =\) _______

\(\frac{5}{7} + \frac{1}{2} =\) _______

\(\frac{5}{6} + \frac{5}{9} =\) _______

\(\frac{1}{5} + \frac{3}{4} =\) _______

\(\frac{4}{7} - \frac{2}{3} =\) _______

\(\frac{3}{8} - \frac{5}{8} =\) _______

\(\frac{1}{2} + \frac{3}{4} =\) _______

\(\frac{2}{7} + \frac{2}{3} =\) _______

\(\frac{2}{3} + \frac{1}{2} =\) _______

\(\frac{3}{7} - \frac{3}{7} =\) _______

\(\frac{1}{3} + \frac{6}{7} =\) _______

Answers


\(\frac{5}{7} - \frac{4}{9} = \frac{17}{63}\)

\(\frac{2}{7} + \frac{6}{7} = 1 \frac{1}{7}\)

\(\frac{5}{8} - \frac{3}{8} = \frac{1}{4}\)

\(\frac{2}{3} - \frac{1}{9} = \frac{5}{9}\)

\(\frac{2}{5} + \frac{3}{4} = 1 \frac{3}{20}\)

\(\frac{1}{2} + \frac{4}{7} = \frac{15}{14}\)

\(\frac{5}{6} + \frac{1}{2} = 1 \frac{1}{3}\)

\(\frac{1}{2} + \frac{3}{8} = \frac{7}{8}\)

\(\frac{7}{8} + \frac{3}{8} = 1 \frac{1}{4}\)

\(\frac{1}{2} + \frac{5}{6} = 1 \frac{1}{3}\)

\(\frac{1}{7} + \frac{8}{9} = \frac{65}{63}\)

\(\frac{1}{3} + \frac{5}{9} = \frac{8}{9}\)

\(\frac{6}{7} + \frac{4}{7} = 1 \frac{3}{7}\)

\(\frac{1}{4} - \frac{3}{4} = \frac{-1}{2}\)

\(\frac{1}{7} - \frac{5}{8} = \frac{-27}{56}\)

\(\frac{7}{8} + \frac{3}{4} = \frac{13}{8}\)

\(\frac{1}{2} - \frac{7}{8} = \frac{-3}{8}\)

\(\frac{1}{6} - \frac{1}{6} = \frac{0}{1}\)

\(\frac{5}{7} + \frac{1}{2} = 1 \frac{3}{14}\)

\(\frac{5}{6} + \frac{5}{9} = 1 \frac{7}{18}\)

\(\frac{1}{5} + \frac{3}{4} = \frac{19}{20}\)

\(\frac{4}{7} - \frac{2}{3} = \frac{-2}{21}\)

\(\frac{3}{8} - \frac{5}{8} = \frac{-1}{4}\)

\(\frac{1}{2} + \frac{3}{4} = \frac{5}{4}\)

\(\frac{2}{7} + \frac{2}{3} = \frac{20}{21}\)

\(\frac{2}{3} + \frac{1}{2} = 1 \frac{1}{6}\)

\(\frac{3}{7} - \frac{3}{7} = \frac{0}{1}\)

\(\frac{1}{3} + \frac{6}{7} = \frac{25}{21}\)
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