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MathematicsArithmeticFractions → Adding Fractions

Instructions for problem set  Get a common denominator in order to evaluate the following

Questions


\(\frac{2}{3} + \frac{7}{8} =\) _______

\(\frac{1}{2} + \frac{7}{8} =\) _______

\(\frac{2}{3} + \frac{3}{4} =\) _______

\(\frac{2}{7} + \frac{7}{8} =\) _______

\(\frac{3}{4} - \frac{6}{7} =\) _______

\(\frac{4}{9} + \frac{4}{9} =\) _______

\(\frac{1}{2} + \frac{8}{9} =\) _______

\(\frac{2}{3} + \frac{1}{4} =\) _______

\(\frac{2}{3} + \frac{4}{9} =\) _______

\(\frac{3}{7} - \frac{5}{9} =\) _______

\(\frac{2}{7} + \frac{8}{9} =\) _______

\(\frac{1}{7} + \frac{7}{8} =\) _______

\(\frac{1}{8} - \frac{4}{9} =\) _______

\(\frac{1}{4} - \frac{3}{4} =\) _______

\(\frac{6}{7} - \frac{3}{8} =\) _______

\(\frac{6}{7} + \frac{2}{3} =\) _______

\(\frac{1}{3} + \frac{4}{9} =\) _______

\(\frac{4}{5} + \frac{7}{8} =\) _______

\(\frac{1}{2} + \frac{8}{9} =\) _______

\(\frac{1}{3} - \frac{5}{9} =\) _______

\(\frac{3}{4} - \frac{7}{8} =\) _______

\(\frac{1}{2} + \frac{5}{7} =\) _______

\(\frac{5}{6} + \frac{7}{9} =\) _______

\(\frac{5}{6} + \frac{5}{6} =\) _______

\(\frac{2}{7} + \frac{8}{9} =\) _______

\(\frac{4}{5} + \frac{1}{2} =\) _______

\(\frac{5}{7} + \frac{6}{7} =\) _______

\(\frac{2}{5} - \frac{1}{7} =\) _______

Answers


\(\frac{2}{3} + \frac{7}{8} = 1 \frac{13}{24}\)

\(\frac{1}{2} + \frac{7}{8} = 1 \frac{3}{8}\)

\(\frac{2}{3} + \frac{3}{4} = 1 \frac{5}{12}\)

\(\frac{2}{7} + \frac{7}{8} = 1 \frac{9}{56}\)

\(\frac{3}{4} - \frac{6}{7} = \frac{-3}{28}\)

\(\frac{4}{9} + \frac{4}{9} = \frac{8}{9}\)

\(\frac{1}{2} + \frac{8}{9} = \frac{25}{18}\)

\(\frac{2}{3} + \frac{1}{4} = \frac{11}{12}\)

\(\frac{2}{3} + \frac{4}{9} = 1 \frac{1}{9}\)

\(\frac{3}{7} - \frac{5}{9} = \frac{-8}{63}\)

\(\frac{2}{7} + \frac{8}{9} = \frac{74}{63}\)

\(\frac{1}{7} + \frac{7}{8} = 1 \frac{1}{56}\)

\(\frac{1}{8} - \frac{4}{9} = \frac{-23}{72}\)

\(\frac{1}{4} - \frac{3}{4} = \frac{-1}{2}\)

\(\frac{6}{7} - \frac{3}{8} = \frac{27}{56}\)

\(\frac{6}{7} + \frac{2}{3} = 1 \frac{11}{21}\)

\(\frac{1}{3} + \frac{4}{9} = \frac{7}{9}\)

\(\frac{4}{5} + \frac{7}{8} = \frac{67}{40}\)

\(\frac{1}{2} + \frac{8}{9} = 1 \frac{7}{18}\)

\(\frac{1}{3} - \frac{5}{9} = \frac{-2}{9}\)

\(\frac{3}{4} - \frac{7}{8} = \frac{-1}{8}\)

\(\frac{1}{2} + \frac{5}{7} = 1 \frac{3}{14}\)

\(\frac{5}{6} + \frac{7}{9} = \frac{29}{18}\)

\(\frac{5}{6} + \frac{5}{6} = \frac{5}{3}\)

\(\frac{2}{7} + \frac{8}{9} = 1 \frac{11}{63}\)

\(\frac{4}{5} + \frac{1}{2} = \frac{13}{10}\)

\(\frac{5}{7} + \frac{6}{7} = 1 \frac{4}{7}\)

\(\frac{2}{5} - \frac{1}{7} = \frac{9}{35}\)
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