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MathematicsArithmeticFractions → Adding Fractions

Instructions for problem set  Get a common denominator in order to evaluate the following

Questions


\(\frac{1}{2} + \frac{2}{9} =\) _______

\(\frac{3}{4} + \frac{1}{6} =\) _______

\(\frac{1}{7} - \frac{1}{9} =\) _______

\(\frac{5}{6} + \frac{5}{7} =\) _______

\(\frac{1}{9} + \frac{5}{9} =\) _______

\(\frac{8}{9} + \frac{7}{9} =\) _______

\(\frac{1}{7} - \frac{5}{8} =\) _______

\(\frac{5}{6} + \frac{1}{2} =\) _______

\(\frac{4}{5} + \frac{7}{8} =\) _______

\(\frac{2}{3} + \frac{6}{7} =\) _______

\(\frac{1}{7} + \frac{7}{8} =\) _______

\(\frac{1}{2} - \frac{1}{2} =\) _______

\(\frac{2}{7} + \frac{3}{8} =\) _______

\(\frac{1}{9} + \frac{1}{3} =\) _______

\(\frac{2}{5} + \frac{8}{9} =\) _______

\(\frac{1}{3} + \frac{1}{7} =\) _______

\(\frac{5}{6} - \frac{5}{7} =\) _______

\(\frac{3}{5} + \frac{2}{3} =\) _______

\(\frac{7}{8} + \frac{8}{9} =\) _______

\(\frac{1}{6} + \frac{1}{2} =\) _______

\(\frac{2}{3} + \frac{3}{7} =\) _______

\(\frac{1}{4} - \frac{7}{8} =\) _______

\(\frac{3}{7} + \frac{1}{2} =\) _______

\(\frac{2}{3} - \frac{1}{2} =\) _______

\(\frac{1}{3} + \frac{2}{3} =\) _______

\(\frac{2}{7} + \frac{7}{8} =\) _______

\(\frac{1}{4} + \frac{5}{8} =\) _______

\(\frac{2}{3} + \frac{7}{8} =\) _______

Answers


\(\frac{1}{2} + \frac{2}{9} = \frac{13}{18}\)

\(\frac{3}{4} + \frac{1}{6} = \frac{11}{12}\)

\(\frac{1}{7} - \frac{1}{9} = \frac{2}{63}\)

\(\frac{5}{6} + \frac{5}{7} = 1 \frac{23}{42}\)

\(\frac{1}{9} + \frac{5}{9} = \frac{2}{3}\)

\(\frac{8}{9} + \frac{7}{9} = \frac{5}{3}\)

\(\frac{1}{7} - \frac{5}{8} = \frac{-27}{56}\)

\(\frac{5}{6} + \frac{1}{2} = 1 \frac{1}{3}\)

\(\frac{4}{5} + \frac{7}{8} = \frac{67}{40}\)

\(\frac{2}{3} + \frac{6}{7} = \frac{32}{21}\)

\(\frac{1}{7} + \frac{7}{8} = 1 \frac{1}{56}\)

\(\frac{1}{2} - \frac{1}{2} = \frac{0}{1}\)

\(\frac{2}{7} + \frac{3}{8} = \frac{37}{56}\)

\(\frac{1}{9} + \frac{1}{3} = \frac{4}{9}\)

\(\frac{2}{5} + \frac{8}{9} = 1 \frac{13}{45}\)

\(\frac{1}{3} + \frac{1}{7} = \frac{10}{21}\)

\(\frac{5}{6} - \frac{5}{7} = \frac{5}{42}\)

\(\frac{3}{5} + \frac{2}{3} = 1 \frac{4}{15}\)

\(\frac{7}{8} + \frac{8}{9} = 1 \frac{55}{72}\)

\(\frac{1}{6} + \frac{1}{2} = \frac{2}{3}\)

\(\frac{2}{3} + \frac{3}{7} = \frac{23}{21}\)

\(\frac{1}{4} - \frac{7}{8} = \frac{-5}{8}\)

\(\frac{3}{7} + \frac{1}{2} = \frac{13}{14}\)

\(\frac{2}{3} - \frac{1}{2} = \frac{1}{6}\)

\(\frac{1}{3} + \frac{2}{3} = 1\)

\(\frac{2}{7} + \frac{7}{8} = 1 \frac{9}{56}\)

\(\frac{1}{4} + \frac{5}{8} = \frac{7}{8}\)

\(\frac{2}{3} + \frac{7}{8} = 1 \frac{13}{24}\)
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